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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
Let a1,a2,a3,…,an…a_1, a_2, a_3, \ldots, a_n \ldots be an A.P. whose common difference is an integer and SnS_{n} denote the sum of its nn terms. If a1=1,an=300a_1=1, a_n=300 and 15≤n≤5015 \leq n \leq 50, then the ordered pair (Sn−4,an−4)\left(S_{n-4}, a_{n-4}\right) is equal to
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Correct option: A
(2490,248)(2490,248)
Option A (2490, 248) is correct because it is derived from finding the common difference and then calculating Sn−4S_{n-4} and an−4a_{n-4}.

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