JEE CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Hard

1 of 1

Application +4 | -1

{\mathrm{I}^{\mathrm{st}}}\mathrm{\;and\;I}{\mathrm{I}^{\mathrm{nd}}}\mathrm{\;IE}

of Mg are 7.646 and 15.035 eV respectively. The amount of energy needed to convert all the atoms of magnesium into  

\mathrm{M}{\mathrm{g}^{2 + }}

ions present in 12 mg of magnesium vapours is [Given, 1eV = 96.5 kJ

\mathrm{mo}{\mathrm{l}^{ - 1}}

]

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Correct option: C

1.1

Option C (1.1) is correct because it is the result of calculating the total ionization energy for all magnesium atoms.

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