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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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One junction of a certain thermoelectric couple is at a fixed temperature Tr{T_r} and the other junction is at temperature TT. The thermo-electromotive force for this is expressed by E=k(T−Tr)  [T0−12(T+Tr)]E = k\left( {T - {T_r}} \right)\,\,\left[ {{T_0} - \frac{1}{2}\left( {T + {T_r}} \right)} \right]. At temperature T=12T0T = \frac{1}{2}{T_0}, the thermoelectric power is
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Correct option: A
12  k T0\frac{1}{2}\,\,k\,{T_0}
Option A (12k,T0\frac{1}{2}\\ k\\,{T_0}) is correct because it is the result of differentiating the given electromotive force equation with respect to temperature and then substituting the given temperature value.

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