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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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A typical golf ball weighs 40.0 g40.0 \mathrm{~g}. If it is moving with a velocity of 20.0 ms−120.0 \mathrm{~ms}^{-1}, its de-Broglie wavelength is
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Correct option: C
8.28×10−25 nm8.28 \times 10^{-25} \mathrm{~nm}
Option B (8.28×10−32 nm8.28 \times 10^{-32} \mathrm{~nm}) is correct because it is calculated using the de Broglie wavelength formula, λ=hmv\lambda = \frac{h}{mv}.

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