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JEE MATHEMATICS MCQ: FUNCTIONS

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If log⁡616=k\log _6 16=k, then log⁡1824=\log _{18} 24=
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Correct option: B
2(k+2)8−k\frac{2(k+2)}{8-k}
Option B (2(k+2)8−k\frac{{2(k+2)}}{{8-k}}) is correct because it follows from converting the logarithms to base 2 and then expressing log⁡1824\log_{{18}} 24 in terms of k.

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