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JEE MATHEMATICS MCQ: COMBINATIONS

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Application +4 | -1
If an=∑r=0m1  nCr,  then  ∑r=0nr  nCr{a_n} = \sum \limits_{r = 0}^m \frac{1}{{{\;^n}{C_r}}},\;{\text{then}}\;\sum \limits_{r = 0}^n \frac{r}{{{\;^n}{C_r}}} equals
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Correct option: C
12nan\frac{1}{2}n{a_n}
Option C (12\frac{1}{2}n{a_n}) is correct because by using the property of combinations and summing the series in reverse, we can find the required sum.

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