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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Easy
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Application +4 | -1
If the electron in hydrogen atom jumps from the third orbit to second orbit, the wavelength of the emitted radiation is given by
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Correct option: A
λ=365R\lambda = \frac{{36}}{{5R}}
Option A (λ=365R\lambda = \frac{{36}}{{5R}}) is correct because it is derived from the Rydberg formula for the wavelength of emitted radiation when an electron transitions between energy levels.

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