$\mathop {\lim }\limits_{x \to 0} {x^2}\sin \frac{\pi }{x}$, us

JEE MATHEMATICS MCQ: LIMITS

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\lim\limits_{x \to 0} {x^2}\sin \frac{\pi }{x}

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Correct option: B

Option B (0) is correct because x² approaches 0, and sin(π/x) is bounded between -1 and 1, so their product approaches 0.

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