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JEE PHYSICS MCQ: WAVES

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Application +4 | -1
A wave travelling in positive XX-direction with A=0.2 mA = 0.2\,m has a velocity of 360  m/sec.360\,\,m/sec.. If λ=60  m,\lambda = 60\,\,m,, then correct expression for the wave is
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Correct option: C
y=0.2sin⁡[2π(6t−x60)]y = 0.2\sin \left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]
Option C (y=0.2sin⁡[2π(6t−x60)]y = 0.2\sin \left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]) is correct because it represents a wave traveling in the positive X-direction with the given amplitude, velocity, and wavelength.

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