JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

Assuming radius of earth is '

R

', specific heat is '

s

' and angular velocity is '

\omega

' if earth rotation is suddenly stop then find out the increasing the temperature of earth surface.

View answer and explanation

Correct option: A

\Delta T=\frac{\omega^2 R^2}{5 J s}

Option A (

\Delta T=\frac{\omega^2 R^2}{5 J s}

) is correct because the increase in temperature is calculated by equating the rotational kinetic energy to the heat energy gained.

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