${{\rm{N}}_2}$ gas is liberated when $\left[ {{\rm{HCl}} + {\rm{NaN}}{{\rm{O}}_2}} \right]{\rm{\;}}$ reacts with the following compounds (A) ${\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{N}}{{\rm{H}}_2}$ (B) Urea (C) ${\rm{C}}{{\rm{H}}_3}{\rm{CON}}{{\rm{H}}_2}$ (D) ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{N}}{{\rm{H}}_2}$ The answer is

NEET UG CHEMISTRY MCQ: AMINES

1 Medium

1 of 1

Analyzing +4 | -1

{\mathrm{N}_2}

gas is liberated when

\left[ {\mathrm{HCl} + \mathrm{NaN}{\mathrm{O}_2}} \right]\mathrm{\;}

reacts with the following compounds
(A)

\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}

(B) Urea
(C)

\mathrm{C}{\mathrm{H}_3}\mathrm{CON}{\mathrm{H}_2}

(D)

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{N}{\mathrm{H}_2}

The answer is

View answer and explanation

Correct option: A

A, B, C

Option A (A, B, C) is correct because primary aliphatic amines, urea, and amides react with

HCl + NaN{O_2}

to liberate

N_2

gas.