$\mathop \smallint \nolimits_1^2 \,\,{e^x}\,\,\left( {\frac{1}{x}\,\, - \,\,\frac{1}{{{x^2}}}} \right)\,\,dx$ is equal to

$e\,\, - \,\,\frac{{{e^2}}}{2}$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \nolimits_1^2 \,\,{e^x}\,\,\left( {\frac{1}{x}\,\, - \,\,\frac{1}{{{x^2}}}} \right)\,\,dx

is equal to

View answer and explanation

Correct option: B

\frac{{{e^2}}}{2}\,\, - \,\,e

Option B is correct because after applying integration by parts, the integral simplifies to the given expression.

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