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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1

Common feature between

\mathrm{N}_2^{+}

and

\mathrm{O}_2^{+}

is that;

(I) both are isoelectronic.

(II) both have same bond order.

(III) both are paramagnetic.

(IV) both have unpaired, electron in same orbital.

View answer and explanation

Correct option: C

II and III

Option C is correct because both N2+ and O2+ are paramagnetic and have the same bond order of 2.5.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

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The hybridization in sulphur dioxide is

\mathrm{C}{\mathrm{O}_2}

has the same geometry as:

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

The pair of molecules forming strongest hydrogen bonds are Paramagnetism is shown by Which statement is correct? Assertion (A) :

{BF}_3

is a weaker Lewis acid than

{BCl}_3

.

Reason (R) : The planar

{BF}_3

molecule is stabilised to a greater extent than

{BCl}_3

{B}-X \pi

-bonding.