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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

1 Hard

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Application +4 | -1

Taking frequency

f

, velocity

v

and density

\rho

to be the fundamental quantities, then the dimensional formula for momentum will be

View answer and explanation

Correct option: A

\left[ {\rho {v^4}{f^{ - 3}}} \right]

Option A ([

\rho {v^4}{f^{ - 3}}

]) is correct because dimensional analysis, using frequency, velocity, and density as fundamental quantities, yields the dimensions of momentum.

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