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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In a Ī”ABC,a,c,A\Delta ABC,a,c,A are given and b1,b2{b_1},{b_2} are two values, if the third side bb such that b2=2b1{b_2} = 2{b_1}, then sin⁔A\sin A is equal to
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Correct option: B
9a2āˆ’c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}}
Option B 9a2āˆ’c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}} is correct because it is derived by using the cosine rule and the given condition b2=2b1{b_2} = 2{b_1}.

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