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JEE MATHEMATICS MCQ: PARABOLA

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Understanding +4 | -1
The parametric coordinates of any point on the parabola y2=4ax{y^2} = 4ax can be
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Correct option: C
(asin⁡2t,−2asin⁡t)\left( {a{{\sin }^2}t, - 2a\sin t} \right)
Option A (± π2\pm \, \frac{\pi }{2}) is correct because the difference between the eccentric angles of the ends of a pair of conjugate diameters of an ellipse is ± π2\pm \, \frac{\pi }{2}.

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