JEE MATHEMATICS MCQ: INCREASING & DECREASING

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Analyzing +4 | -1

Let

f:(-1, \infty) \rightarrow R

be defined by,

f(x)=\left\{\begin{array}{cc} \frac{\log _e(1+x)}{x}, & x \neq 0 \\ 0, & x=0 \end{array}\right.

then the function

f

View answer and explanation

Correct option: B

Decreases in

(-1, \infty)

Option B is correct. The function decreases in

(-1, \infty)

because its derivative is negative in that interval.

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f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

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a

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\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)