JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Application +4 | -1

The locus of the point of intersection of tangents to the ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

at the points whose eccentric angles differ by

\pi / 2,

View answer and explanation

Correct option: D

\frac{x^2}{a^2}+\frac{y^2}{b^2}=2

Option D (

\frac{x^2}{a^2}+\frac{y^2}{b^2}=2

) is correct because it represents the locus of the intersection point of tangents to the ellipse where the eccentric angles differ by

\pi/2

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