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JEE MATHEMATICS MCQ: PERMUTATIONS

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Analyzing +4 | -1

n

is selected from the set

\{1,2,3, \ldots, 100\}

and the number

2^n+3^n+5^n

is formed. Total number of ways of selecting

n

, so that the formed number is divisible by 4, is equal to

View answer and explanation

Correct option: B

49

Option B (49) is correct because only even values of n make

2^n + 3^n + 5^n

divisible by 4, and there are 49 even numbers between 2 and 100 inclusive.

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