Skip to main content
Back to CURRENT ELECTRICITY

JEE PHYSICS MCQ: CURRENT ELECTRICITY

1 Medium
1 of 1
Remembering +4 | -1
To deposit one gm equivalent of an element at an electrode, the quantity of electricity needed is
View answer and explanation
Correct option: D
96500  coulombs96500\,\,coulombs
Option D (96500  coulombs96500\,\,coulombs) is correct because Faraday's constant (approximately 96500 coulombs) is the charge required to deposit one gram equivalent of an element.

More Questions from CURRENT ELECTRICITY

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.