$\mathop {\lim }\limits_{x \to 0} \frac{{x\cos x - \log \left( {1 + x} \right)}}{{{x^2}}}$ equals

JEE MATHEMATICS MCQ: LIMITS

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\lim\limits_{x \to 0} \frac{{x\cos x - \log \left( {1 + x} \right)}}{{{x^2}}}

equals

View answer and explanation

Correct option: A

\frac{1}{2}

Option A (

\frac{1}{2}

) is correct because using Taylor series expansions for cos(x) and log(1+x) allows us to evaluate the limit.

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