JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

What is the de Broglie wavelength? Assume that one mole of protons has a mass equal to

1 \mathrm{~g}?

(h=6.626 \times

10^{-27} \text{erg s})

View answer and explanation

Correct option: B

1.33 \times 10^{-3}\mathop {\text{A}}\limits^ \circ

Option B (

1.33 \times 10^{-3}\mathop {\text{A}}\limits^ {\circ}

) is correct because the de Broglie wavelength is calculated using the formula

\lambda = \frac{{h}}{{mv}}

, where m is the mass of one proton and v is the velocity.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.