The major product formed in the following reaction is $C{H_3} - \begin{array}{*{20}{c}} {C{H_3}} \\ | \\ C \\ | \\ H \end{array} - C{H_2}I\xrightarrow{{C{H_3}OH}}$

$C{H_3} - \begin{array}{*{20}{c}} {C{H_3}} \\ | \\ C \\ | \\ {OC{H_3}} \end{array} - C{H_3}$

$C{H_3} - \begin{array}{*{20}{c}} {C{H_3}} \\ | \\ C \\ | \\ H \end{array} - C{H_2}OC{H_3}$

$C{H_3} - \begin{array}{*{20}{c}} H \\ | \\ C \\ | \\ {OC{H_3}} \end{array} - C{H_2}C{H_3}$

$C{H_3} - \begin{array}{*{20}{c}} {C{H_3}} \\ | \\ C \\ {} \\ {} \end{array} = C{H_2}$

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NEET UG CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

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The major product formed in the following reaction is

C{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ H \end{array} - C{H_2}I\xrightarrow{{C{H_3}OH}}

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Correct option: D

C{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ {OC{H_3}} \end{array} - C{H_3}

Option D is correct because the reaction proceeds via SN1 mechanism due to the formation of a stable tertiary carbocation, leading to the substitution of iodine with methoxy group.

NEET UG CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

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