The phase difference between current and voltage in an $\mathrm{AC}$ circuit is $\pi / 4$ radian. If the frequency of $\mathrm{AC}$ is $50 \mathrm{~Hz}$, then the phase difference is equivalent to the time difference :

NEET UG PHYSICS MCQ: WAVES

1 Easy

1 of 1

Application +4 | -1

The phase difference between current and voltage in an

\mathrm{AC}

circuit is

\pi / 4

radian. If the frequency of

\mathrm{AC}

50 \mathrm{~Hz}

, then the phase difference is equivalent to the time difference :

View answer and explanation

Correct option: D

2.5 \mathrm{~ms}

Option D (

2.5 \text{{ ms}}

) is correct because the time difference is calculated by dividing the phase difference by the angular frequency, which is

2\pi

times the frequency.

Practice All Chapter MCQs →

1000\,\,Hz

1500\,\,\mathrm{m}{\mathrm{s}^{ - 1}}

r

40.0 \mathrm{kHz}

360 \mathrm{~km} / \mathrm{h}

1450 \mathrm{~m} / \mathrm{s}