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JEE PHYSICS MCQ: WAVES

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Analyzing +4 | -1
If x=asin⁡[ωt+(π/3)]x=a \sin [\omega t+(\pi / 3)] and x′=acos⁡ωtx^{\prime}=a \cos \omega t, then what is the phase difference between two waves?
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Correct option: B
π/6\quad \pi / 6
Option B (π/6\quad \pi / 6) is correct because the phase difference is calculated by converting cosine to sine and then finding the difference in the phase angles.

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