The binding energy per nucleon for deuteron and helium are ${\rm{1}}{\rm{.1}}\,\,{\rm{MeV}}$ and ${\rm{7}}{\rm{.0}}\,\,{\rm{MeV}}$. The energy released when two deuterons fuse to form a helium nucleus is

${\rm{23}}{\rm{.6}}\,\,{\rm{MeV}}$

${\rm{2}}{\rm{.2}}\,\,{\rm{MeV}}$

${\rm{30}}{\rm{.2}}\,\,{\rm{MeV}}$

${\rm{3}}{\rm{.6}}\,\,{\rm{MeV}}$

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JEE PHYSICS MCQ: NUCLEI

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The binding energy per nucleon for deuteron and helium are

\mathrm{1}\mathrm{.1}\,\,\mathrm{MeV}

and

\mathrm{7}\mathrm{.0}\,\,\mathrm{MeV}

. The energy released when two deuterons fuse to form a helium nucleus is

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Correct option: A

\mathrm{23}\mathrm{.6}\,\,\mathrm{MeV}

Option A (

\mathrm{23}\mathrm{.6}\,\mathrm{MeV}

) is correct because the energy released is the difference between the binding energy of the helium nucleus and the total binding energy of the two deuterons.

JEE PHYSICS MCQ: NUCLEI

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