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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let f:[−2,3]→[0,∞)f:[-2,3] \rightarrow[0, \infty) be a continuous function such that f(1−x)=f(x)f(1-x)=f(x) for all x∈[−2,3]x \in[-2,3].
If R1R_1 is the numerical value of the area of the region bounded by y=f(x),x=−2,x=3y=f(x), x=-2, x=3 and the axis of xx and R2=∫−23xf(x)dxR_2=\int_{-2}^3 x f(x) d x, then:
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Correct option: D
R1=2R2\mathrm{R}_1=2 \mathrm{R}_2
Option D (R1=2R2\mathrm{R}_1=2 \mathrm{R}_2) is correct because by using the property of definite integrals and the given condition f(1−x)=f(x)f(1-x)=f(x), we can show that 2R2=R12R_2 = R_1.

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