NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

If the resultant of two forces

\left( {A + B} \right)\,and\,\left( {A - D} \right)\,is\,\sqrt {{A^2} + {B^2}}

, then the angle between these forces is

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Correct option: C

{\cos ^{ - 1}}\left[ { - \frac{{{A^2} + {B^2}}}{{2\left( {{A^2} - {B^2}} \right)}}} \right]

Option C (

{\cos ^{ - 1}}\left[ { - \frac{{{A^2} + {B^2}}}{{2\left( {{A^2} - {B^2}} \right)}}} \right]

) is correct because the angle between the forces is found using the law of cosines and simplifying the expression.

More Questions from MOTION IN PLANE

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)