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NEET UG PHYSICS MCQ: RAY OPTICS

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Application +4 | -1
If eye is kept at a depth hh inside water of refractive index and viewed outside, then the diameter of the circle through which the outer objects become visible, will be
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Correct option: C
2 hμ2−1\frac{{2\,h}}{{\sqrt {{\mathrm{\mu }^2} - 1} }}
Option C (2 hµ2−1\frac{{2\,h}}{{\sqrt {{{{µ}}^2} - 1} }}) is correct because it is derived from Snell's law and trigonometric relationships, considering the critical angle for total internal reflection.

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