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JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
Given, Force =αdensity+  β3= \frac{\alpha }{{\mathrm{density} + \mathrm{\;}{\mathrm{\beta }^3}}} What are the dimensions of α,β?\mathrm{\alpha },\mathrm{\beta }?
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Correct option: D
[M2L−2T2],  [ML−3]\left[ {{\mathrm{M}^2}{\mathrm{L}^{ - 2}}{\mathrm{T}_2}} \right],\mathrm{\;}\left[ {\mathrm{M}{\mathrm{L}^{ - 3}}} \right]
Option C ([M2 L-2 T-2], [M1/3 L-1]) is correct because it is derived from equating dimensions of force and density with the given expression.

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