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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Let A1{A_1} be the area of the parabola y2=4ax{y^2} = 4ax lying between vertex and latusrectum and A2{A_2} be the area between latusrectum and double ordinate x=2ax = 2a. Then, A1/A2={A_1}/{A_2} =
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Correct option: B
(22+1)/7\left( {2\sqrt 2 + 1} \right)/7
Option B is correct because the ratio of the areas A1 and A2 is calculated using definite integrals and simplification, resulting in (22\sqrt{2} + 1)/7.

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