JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

The dimension of

a \times b

in the relation

E = \frac{{b - {x^2}}}{{at}},\,

where

E

is the energy,

x

is the displacement and

t

is time are

View answer and explanation

Correct option: B

{M^{ - 1}}{L^2}T

Option B (

{M^{ - 1}}{L^2}T

) is correct because by equating dimensions, we find the dimension of 'a' and 'b' and then multiply them to get the dimension of a x b.

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