JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

Example 9. If

a_1, a_2, a_3, \ldots, a_{2 n+1}

are in

A P

, then

\left(a_{2 n+1}+a_1\right)+\left(a_{2 n}+a_2\right)+\ldots+\left(a_{n+2}+a_n\right)

is equal to

View answer and explanation

Correct option: C

2 n a_{n+1}

Option C (

2 n a_{n+1}

) is correct because it is derived from the property that the sum of terms equidistant from the beginning and end of an AP is constant.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →

A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}