A composite rod made of copper ($\alpha = 1.8 \times {10^{ - 5}}{{\rm{K}}^{ - 1}}$) and steel (${\rm{\alpha }} = 1.2 \times {10^{ - 5}}{{\rm{K}}^{ - 1}}$) is heated. Then

It bends with copper on concave side

NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Understanding +4 | -1

A composite rod made of copper (

\alpha = 1.8 \times {10^{ - 5}}{\mathrm{K}^{ - 1}}

) and steel (

\mathrm{\alpha } = 1.2 \times {10^{ - 5}}{\mathrm{K}^{ - 1}}

) is heated. Then

View answer and explanation

Correct option: A

It bends with steel on concave side

Option A (It bends with steel on concave side) is correct because steel has a lower coefficient of thermal expansion than copper, causing it to be on the concave side when heated.

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is placed in an insulation box of wall thickness

1 \mathrm{~cm}

. The box keeping the ice cube at

0^{\circ} \mathrm{C}

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. The rate of melting of ice is approximately.

(Latent heat of fusion of ice is

3.4 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}

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\left. {0.05{\text{W}}{{\text{m}}^{ - 1}}^\circ {{\text{C}}^{ - 1}}} \right)

A black body radiates heat energy at the rate of

2 \times 10^5 \mathrm{~J} / \mathrm{sm}^2

at temp. of

127^{\circ} \mathrm{C}

. The temp of black body at which rate becomes

32 \times 10^5 \mathrm{~J} / \mathrm{s}-\mathrm{m}^2

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\sigma

+ \frac{1}{2}

for a material, then the material is