JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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\frac{{\frac{1}{{2!}} + \frac{1}{{4!}} + \frac{1}{{6!}} + \ldots }}{{1 + \frac{1}{{3!}} + \frac{1}{{5!}} + \ldots }}

equals

View answer and explanation

Correct option: B

\frac{{e - 1}}{{e + 1}}

Option B (

\frac{{e - 1}}{{e + 1}}

) is correct because the expression can be simplified using the definitions of hyperbolic sine and cosine in terms of exponentials.

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