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JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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If cos⁡(α+β)=0\cos (\alpha+\beta)=0 then cosec⁡(α−β)=\operatorname{cosec}(\alpha-\beta)=
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Correct option: D
±sec⁡2β\pm \sec 2 \beta
Option D (±sec⁡2β\pm \sec 2 \beta) is correct because from cos⁡(α+β)=0\cos(\alpha + \beta) = 0, we can derive that α+β=(2n+1)π2\alpha + \beta = (2n+1)\frac{\pi}{2}, and then find cosec⁡(α−β)\operatorname{cosec}(\alpha - \beta) in terms of β\beta.

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