Skip to main content
Back to THERMODYNAMICS

NEET UG PHYSICS MCQ: THERMODYNAMICS

1 Medium
1 of 1
Application +4 | -1
A gas under constant pressure of 4.5×1054.5 \times {10^5} Pa when subjected to 800 kJ of heat changes the volume from0.5m30.5{\mathrm{m}^3} to 2.0m32.0{\mathrm{m}^3}. The change in the internal energy of the gas is
View answer and explanation
Correct option: D
1.25×105J1.25 \times {10^5}\mathrm{J}
Option D (1.25×105J1.25 \times {10^5}\mathrm{J}) is correct because the change in internal energy is calculated using the first law of thermodynamics, accounting for the work done at constant pressure.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.