What volume of 0.40 $M$ ${\rm{N}}{{\rm{a}}_2}{{\rm{S}}_2}{{\rm{O}}_3}$ would be required to react with the ${{\rm{I}}_2}$ liberated by adding excess of KI to 50 mL of 0.20 $M$ ${\rm{CuS}}{{\rm{O}}_4}$ solution?

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Medium

1 of 1

Application +4 | -1

What volume of 0.40

M

\mathrm{N}{\mathrm{a}_2}{\mathrm{S}_2}{\mathrm{O}_3}

would be required to react with the

{\mathrm{I}_2}

liberated by adding excess of KI to 50 mL of 0.20

M

\mathrm{CuS}{\mathrm{O}_4}

solution?

View answer and explanation

Correct option: B

25 mL

Option B (25 mL) is correct because the milliequivalents of Na2S2O3 equals the milliequivalents of CuSO4.

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{H_2}O.

mol\,\,k{g^{ - 1}})

2.24 {~L}

{CH}_4

{CO}_2

0.5 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4

0.5 \mathrm{~g}

\mathrm{Cu}(\mathrm{II})