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JEE MATHEMATICS MCQ: COMBINATIONS

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If nn is even and nC0<nC1<nC2<....<nCr>nCr+1>nCr+2>....>nCn′^n{C_0}{ < ^n}{C_1}{ < ^n}{C_2} < ....{ < ^n}{C_r}{ > ^n}{C_{r + 1}}{ > ^n}{C_{r + 2}} > ....{ > ^n}{C_{n'}} then, r=r =
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Correct option: A
n2\frac{n}{2}
Option A (n2\frac{n}{2}) is correct because the binomial coefficients nCr^{n}C_r are maximized when rr is closest to n2\frac{n}{2}, and since nn is even, r=n2r = \frac{n}{2} gives the maximum value.

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