JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\sin \theta_1-\sin \theta_2=a

and

\cos \theta_1+\cos \theta_2=b

, then

View answer and explanation

Correct option: B

a^2+b^2 \leq 4

Option B (

a^2+b^2 \leq 4

) is correct because by squaring and adding the given equations, and using trigonometric identities, we find that

a^2 + b^2 = 2 + 2\cos(\theta_1 + \theta_2)

, which is always less than or equal to 4.

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