$I = \left| {\,\mathop \smallint \nolimits_2^5 \,\,\frac{{\sin \,\,x\,\,dx}}{{(1 + {x^2}}}\,} \right|,\,\,{\rm{then}}$

$I$ lies in the interval $\left( {\frac{1}{4},\,\,\frac{1}{5}} \right)$

$I$ liesin the interval $\left( {\frac{1}{5},\,\,\frac{1}{6}} \right)$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

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Analyzing +4 | -1

I = \left| {\,\int \nolimits_2^5 \,\,\frac{{\sin \,\,x\,\,dx}}{{(1 + {x^2}}}\,} \right|,\,\,\mathrm{then}

View answer and explanation

Correct option: D

I \le \frac{3}{{10}}

Option D (

I \le \frac{3}{{10}}

) is correct because the integral is bounded above by

\frac{3}{10}

by using properties of inequalities and integrals.

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