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NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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The rate of flow of liquid through a capillary tube of radiusrr isVV when the pressure difference across the two ends of the capillary is pp. If pressure is increased by 3 pp and radius is reduced to r/2r/2, then the rate of flow becomes
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Correct option: C
V/4V/4
Option C (V/4V/4) is correct because the rate of flow is proportional to the pressure difference and the fourth power of the radius, so increasing the pressure by a factor of 4 and halving the radius results in a flow rate that is 1/4 of the original.

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