JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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{a}_0

is denoted as the Bohr radius of hydrogen atom, then what is the de-Broglie wavelength

(\lambda)

of the electron present in the second orbit of hydrogen atom?

[ n :

any integer]

View answer and explanation

Correct option: B

\frac{8 \pi a_0}{n}

Option B (

\frac{8 \pi a_0}{n}

) is correct because the de-Broglie wavelength is calculated using the circumference of the orbit and Bohr's radius.

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