JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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Application +4 | -1

The equation(s) of the tangent(s) to the curve

y = {x^4}

from the point (2, 0) not on the curve is given by

View answer and explanation

Correct option: C

y - \frac{{4096}}{{81}} = \frac{{2048}}{{27}}\left( {x - \frac{8}{3}} \right)

Option C (

y - \frac{{4096}}{{81}} = \frac{{2048}}{{27}}\left( {x - \frac{8}{3}} \right)

) is correct because it represents the tangent to the curve

y = {x^4}

from the point (2, 0) not on the curve.

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a

y=x^3-a x

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C

y^3-3 x y+2=0

H

\mathrm{C}

x

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y

y-e^{x y}+x=0

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\theta = \left( {2k + 1} \right)\pi ,\;k \in Z