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JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Phenol → (i) H+(i) CHCl3/NaOH\xrightarrow[\text { (i) } {H}^{+}]{\text {(i) }{CHCl}_3 /{NaOH}} Salicylaldehyde. This reaction is known as
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Correct option: D
Reimer-Tiemann reaction
Option D (Reimer-Tiemann reaction) is correct because the reaction of phenol with chloroform in the presence of NaOH to form salicylaldehyde is the Reimer-Tiemann reaction.

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