If $ x^{2}-4 x+5-\sin y=0, y \in[0,2 \pi] $, then

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

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Application +4 | -1

x^{2}-4 x+5-\sin y=0, y \in[0,2 \pi]

, then

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Correct option: D

x=2, y=\pi / 2

Option D is correct because it satisfies the given equation when the left-hand side is minimized and the right-hand side is maximized, both equaling 1.

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