A volume of $500 \mathrm{~ml}$ of a $0.1 \mathrm{~M}$ solution of ${AgNO}_3$ is added to $500 \mathrm{~ml}$ of $0.1 \mathrm{~M}$ solution of ${KCl}.$ The concentration of nitrate ion in the resulting solution is

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Hard

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Application +4 | -1

A volume of

500 \mathrm{~ml}

of a

0.1 \mathrm{~M}

solution of

{AgNO}_3

is added to

500 \mathrm{~ml}

0.1 \mathrm{~M}

solution of

{KCl}.

The concentration of nitrate ion in the resulting solution is

View answer and explanation

Correct option: A

0.05 \mathrm{~M}

Option A (

0.05 \mathrm{~M}

) is correct because the concentration of nitrate ions is calculated by dividing the moles of nitrate by the total volume.

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