How many grams of ice at $-14^{\circ} \mathrm{C}$ are needed to cool $200 \mathrm{~g}$ of water from $25^{\circ} \mathrm{C}$ to $10^{\circ} \mathrm{C}$ ? Take specific heat of ice $=0.5 \mathrm{cal} / \mathrm{g} /{ }^{\circ} \mathrm{C}$ and latent heat of ice $=80 \mathrm{cal} / \mathrm{g}$.

NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Hard

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Application +4 | -1

How many grams of ice at

-14^{\circ} \mathrm{C}

are needed to cool

200 \mathrm{~g}

of water from

25^{\circ} \mathrm{C}

10^{\circ} \mathrm{C}

? Take specific heat of ice

=0.5 \mathrm{cal} / \mathrm{g} /{ }^{\circ} \mathrm{C}

and latent heat of ice

=80 \mathrm{cal} / \mathrm{g}

View answer and explanation

Correct option: A

Option A (31) is correct because it calculates the mass of ice needed by equating the heat lost by the water to the heat gained by the ice to warm up and melt.

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