JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The value of the integral

\int\limits_{{-1}}^3\left(\tan ^{-1} \frac{x}{x^2+1}+\tan ^{-1} \frac{x^2+1}{x}\right) d x

is equal to

View answer and explanation

Correct option: B

2 \pi

Option B (

2 \pi

) is correct because the expression inside the integral simplifies to

\frac{\pi}{2}

, and the integral of a constant is straightforward.

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