Identify the correct order of solubility of ${\rm{N}}{{\rm{a}}_2}{\rm{S}},{\rm{CuS}}$ and ${\rm{ZnS}}$ in aqueous medium:

${\rm{N}}{{\rm{a}}_2}{\rm{S}} > ZnS > CuS$

${\rm{CuS}} > ZnS > N{{\rm{a}}_2}{\rm{S}}$

${\rm{ZnS}} > N{{\rm{a}}_2}{\rm{S}} > CuS$

${\rm{N}}{{\rm{a}}_2}{\rm{S}} > CuS > ZnS$

JEE CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Hard

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Understanding +4 | -1

Identify the correct order of solubility of

\mathrm{N}{\mathrm{a}_2}\mathrm{S},\mathrm{CuS}

and

\mathrm{ZnS}

in aqueous medium:

View answer and explanation

Correct option: D

\mathrm{N}{\mathrm{a}_2}\mathrm{S} > ZnS > CuS

Option D (

\mathrm{N}{\mathrm{a}_2}\mathrm{S} > ZnS > CuS

) is correct because sodium salts are highly soluble, and the

K_{sp}

value of

\mathrm{CuS}

is less than

\mathrm{ZnS}

, making

\mathrm{ZnS}

more soluble than

\mathrm{CuS}